This is easy when we have a length of 8 and a width of 4. We then multiply 8 x 4 and know that the area is 32!
But, what if we have a length of (x+2) and a width of (x+3) like the image below? How do we multiply that?!
What we need to figure out, then, is how to multiply (x+2) by (x+3).
HOW TO MULTIPLY BINOMIALS
Before multiplying binomials, let's review the distributive property.
We learned in class that it's important to polite. That means that if you knock on someone's door, you have say hello to everyone inside!
Example 1: 5 (4x + 2) means that we must share the 5 with 4x AND with 2.
5 times 4x = 20x
5 times 2 = 10
So, we get 20x and 10 = 20x + 10.
Example 2: x (2x + 4) means that we must share the x on the outside with x AND 4.
x times x = 2x^2
x times 4 = 4x
So, we get 2x^2 and 4x = 2x^2 + 4x.
Try out these:
1. x (x + 6)
2. x (2x + 1)
3. 2x (x + 3)
4. 3x (2x + 1)
Now that we have that ironed that out, we're ready for the big leagues. Looking back at Example 2, we see x (2x + 4).
But, what if it was (x + 1) (2x + 4)? I use the distributive property just like before!
First, I have to share the x with (2x + 4). I am going to pretend that the 1 doesn't exist. When I do that, I get 2x^2 + 4x, just like we did above.
Now, the plot thickens. Instead of ignoring the 1 like I did above, I'm now going to ignore the x. I'm going to share 1 with (2x + 4). When I do that, I get 2x (1 times 2x = 2x) and 4 (1 times 4 = 4). So, it is 2x + 4.
All I need to do is combine all the multiplication I just did. I have 2x^2 + 4x and I have 2x + 4.
When I put it all together, I get: 2x^2 + 4x + 2x + 4.
Again, all I did was apply the distributive property to figure out the answer. First, I shared x with everything in the second parentheses. Then, I shared 1 with everything in the second parentheses. Then, I combined!
Example 2 of multiplying binomials:
(2x + 1) (x + 5)
First, I am going to share the 2x with everything inside (x + 5). When I do that, I get 2x times x = 2x^2 and 2x times 5 = 10x. I put that all together and get 2x^2 + 10x.
Second, I am going to share the 1 with everything inside (x + 5). When I do that, I get 1 times x = 1x and 1 times 5 = 5. I put that all together and get 1x + 5.
Now, I am going to combine everything together and write: 2x^2 + 10x + 1x + 5.
There I have it!
Now, practice doing the same thing with the problems below:
1. (x + 2) (x + 4)
2. (x + 4) (2x + 3)
3. (2x + 2) (x + 3)
4. (3x + 1) (x + 2)
5. (2x + 4) (x + 5)
6. (6x + 2) (4x + 3)
7. (5x + 1) (2x + 4)